Problem in if-else if-else structure
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Hi, I have written the following program. But it does not output the result I get from manual calculations. Perhaps I have gone wrong in writing the logic. The program is as below.
if X1(i)==a(i) && X2(i)==b(i)
t(i)= a(i)* b(i);
else if X1(i)== a(i) && X2(i)==NaN && X1(i+1)==a(i+1) && X2(i+1)==NaN
t(i)= a(i)* a(i+1);
else if X1(i)== a(i) && X2(i)==NaN && X1(i+1)==NaN && X2(i+1)==b(i+1)
t(i)= a(i)* b(i+1);
else if X1(i)==NaN && X2(i)== b(i)&& X1(i+1)==a(i+1) && X2(i+1)==NaN
t(i)= b(i)* a(i+1);
else if X1(i)==NaN && X2(i)== b(i)&& X1(i+1)==NaN && X2(i+1)==b(i+1)
t(i)= b(i)* b(i+1);
else
t(i)= 0;
end
end
end
end
end
The input is as below. X1=NaN a(2) NaN a(4) a(5) NaN NaN
X2= NaN b(2) b(3) NaN b(5) NaN NaN
i=1:7 and i=8 equals to i=1
The output is as below.
t= 0 c 0 0 d 0 0
But there should be output at t(3) and t(4). Can anybody point out where I went wrong? Thanks
1 commentaire
KalMandy
le 11 Nov 2016
Réponses (1)
James Tursa
le 11 Nov 2016
Modifié(e) : James Tursa
le 11 Nov 2016
You can't compare to NaN with the == operator, since NaN is not equal to anything (including itself). You must use the isnan function. E.g.,
else if X1(i)== a(i) && X2(i)==NaN && X1(i+1)==a(i+1) && X2(i+1)==NaN
should be
else if X1(i)== a(i) && isnan(X2(i)) && X1(i+1)==a(i+1) && isnan(X2(i+1))
etc.
For example,
>> a = nan
a =
NaN
>> a == nan
ans =
0
>> a == a
ans =
0
6 commentaires
Walter Roberson
le 11 Nov 2016
What error message are you seeing?
KalMandy
le 11 Nov 2016
James Tursa
le 11 Nov 2016
Please show the exact code you are using to build X1 and X2.
KalMandy
le 11 Nov 2016
KalMandy
le 11 Nov 2016
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