Can someone help me graph this function

It's an Hyperboloid of 2 sheets ( -x^2/a^2 - y^2/b^2 + z^2/c^2 =1) Also if the equation =0 instead of 1 how would you change it? Thank you.

 Réponse acceptée

Image Analyst
Image Analyst le 24 Nov 2016
Try using meshgrid() to get all possible combinations of x and y in a range you specify:
% Declare some constants.
fontSize = 20;
a=1;
b=2;
c=3;
numElements = 30;
constant = 1; % or 0, whichever you want.
% Define range of x and y axes.
x = linspace(-2*a, 2*a, numElements);
y = linspace(-2*b, 2*b, numElements);
% Get every possible combination of x and y.
[X, Y] = meshgrid(x, y);
% Construct function.
Z1 = c * sqrt(constant + X.^2 / a^2 + Y.^2 / b^2);
Z1 = reshape(Z1, [], length(y));
surf(Z1);
Z2 = -c * sqrt(constant + X.^2 / a^2 + Y.^2 / b^2);
Z2 = reshape(Z2, [], length(y));
hold on;
surf(Z2);
% Fancy up the plot
grid on;
xlabel('X', 'FontSize', fontSize);
ylabel('Y', 'FontSize', fontSize);
zlabel('Z', 'FontSize', fontSize);
% Set up figure properties:
% Enlarge figure to full screen.
set(gcf, 'Units', 'Normalized', 'OuterPosition', [0 0 1 1]);
% Get rid of tool bar and pulldown menus that are along top of figure.
% set(gcf, 'Toolbar', 'none', 'Menu', 'none');
% Give a name to the title bar.
set(gcf, 'Name', 'Demo by ImageAnalyst', 'NumberTitle', 'Off')

Plus de réponses (1)

Roger Stafford
Roger Stafford le 24 Nov 2016
Modifié(e) : Roger Stafford le 24 Nov 2016
X = -2*a:.001*a:2*a;
Y = -2*b:.001*b:2*b;
Z1 = c*sqrt(1+X.^2/a^2+Y.^2/b^2);
Z2 = -c*sqrt(1+X.^2/a^2+Y.^2/b^2);
surf(X,Y,Z1)
hold on
surf(X,Y,Z2)
If a 0 is used instead of a 1, then make that substitution in the expressions for Z1 and Z2.

2 commentaires

Dante Truong
Dante Truong le 24 Nov 2016
Your code it said "Undefined function or variable 'a'."
Roger Stafford
Roger Stafford le 24 Nov 2016
You have to specifically define all three quantities, a, b, and c in order to get a graph. You can't leave them as merely symbolic variables.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Discrete Data Plots dans Centre d'aide et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by