How do I go about plotting this function in MATLAB?

smys x; smys y; f = (1 / 2*pi*sqrt(3)) * exp((4*x*x - 8*x + y*y + 2*x*y - 2*y + 4) / 3); plot(f);

It is just going to be on an x-y plane with a range of [-3, 3] and a domain of [-3, 3].

Answer 1

[Niels]

Hi Paul,

first of all, there is no need to use syms if you just want to create a function.

you can use function handle and create an anonymus function: (in addition i think you got something wrong in your function, or it wont do as you desire

look at

(1 / 2*pi*sqrt(3)) = 1/2   *  pi   * sqrt(2)

i guess you want

1 / (2*pi*sqrt(3)) = 1/2   /  pi   / sqrt(2)

create the function f(x,y), the dots are necessary (read about function handles and anonymous functions

f = @(x,y) 1 ./ (2*pi.*sqrt(3)) .* exp((4*x.*x - 8*x + y.*y + 2*x.*y - 2*y + 4) ./ 3);

now you need to set the interval in which the function shall be plotted

x=linspace(Start,End,NumberOfPoints);
y=linspace(Start,End,NumberOfPoints);

plot(x,y,f(x,y))