Matlab's Movsum() doesn't start calc at defined starting point X in frame [X X+t]

Suppose the following:

A = [1;2;3;4;5;6;7];
A1 = table(A);

The following sums current and 2 following cells beneath:

A2 = movsum(A1{:, 1:end}, [0 2], 'Endpoints', 'fill');`

What I want is the sum of what above movsum() does, but without considering the current cell (0 in [0 2]). The very first value of this calculation should be 5 (2+3) (and appear in the first row of table A3), the second 7 (3+4) etc. How do I have to adapt my following code for it to do the intended calculations? How about if I wanna take this rationale one step further, i.e. exclude current + following cell from my movsum() calculation?

A3 = movsum(A1{:, 1:end}, [1 2], 'Endpoints', 'fill');

... because A3 returns:

Answer 1

[Steven Lord]

For the first, eliminating the current cell:

A = 1:7;
B1 = movsum(A, [0 2]);
B2 = A; % Technically movsum(A, [0 0]) but that's just A itself
C = B1-B2

For the second, eliminating the current and next cell:

D = 1:7;
E1 = movsum(D, [1 2]);
E2 = movsum(D, [0 1]);
F = E1-E2

If you want more complicated patterns, treat the windows as sets and use the inclusion-exclusion principle to determine which movsum calls you need to add or subtract. For instance, to get a window like:

pattern = [1 0 1 0 1]

where 1 means it's counted and 0 means it's not, you can write this as:

    [1 1 1 0 0] ... % movsum(A, [2 0]), two previous points plus current point
  - [0 1 1 1 0] ... % movsum(A, [1 1]), one previous point, current point, one next point
  + [0 0 1 1 1]     % movsum(A, [0 2]), current point plus two next points

This is

A = (1:10).^2;
B = movsum(A, [2 0]) - movsum(A, [1 1]) + movsum(A, [0 2])

As a spot check, according to the pattern B(5) should be A(3)+A(5)+A(7) and it is.