converting a struct array fildname to an array

Hi all,

I'm having a struct array of arrays in which I store an array to one of its fieldnames:

o(1).color = [100, 256, 60]
o(2).color = [100, 100, 0]
o(3).color = [100, 0, 60]

and I want to extract all the values in "color" fieldname into a an array forming:

COLOR = [[100, 256, 60] ; [100, 100, 0] ; 100, 0, 60]]

the problem is when I use:

COLOR = [o(:).color];

I get:

COLOR = [100, 256, 60, 100, 100, 0, 100, 0, 60]

which is not what I want. any solution?

Thanks,

Answer 1

[Thomas]

col = [o(:).color];
new_color=reshape(col,3,[])'

This should help

[Payam Parsinejad]

Thanks Thomas; that does it :)

[Thomas]

Please consider accepting the answer so that others know that a solution has been obtained..

Answer 2

[Payam Parsinejad]

another sort of related question:

I have a vector, X, holding some values:

X = [1,3,5,2] Also I have a struct array, objects:

objects(1).x =#
objects(2).x =#
objects(3).x =#
objects(4).x =#

what I want to do is to assign all the values (or some) in X to their corresponding index number in objects.x. i.e.

X -> objects.x

so that I have: objects(1).x =1 objects(2).x =3 objects(3).x =5 objects(4).x =2

any solution?

Thanks, Payam

[Thomas]

X = [1,3,5,2]

for i=1:length(X)

object(i).x=X(i);

end

[Payam Parsinejad]

Hi Thomas,

Can I do such process without using for loop?!

Thanks,

Payam