Using repelem without prior knowledge of the number of matrix dimensions

5 vues (au cours des 30 derniers jours)
Emmanouil
Emmanouil le 6 Fév 2017
Modifié(e) : Stephen23 le 6 Fév 2017
Hello,
I have a matrix A that can be either 3D, 4D, 5D etc. I want to repeat the elements of the last dimension x times. This can be accomplished by using the following expressions: repelem(A,1,1,x) for 3D and repelem(A,1,1,1,x) for 4D matrices. However, since I do not know the number of matrix dimensions in advance, these expressions do not help me. Ideally, I would like to use repelem like repmat e.g. repelem(A,[1,1,x]) for 3D and repelem(A,[1,1,1,x]) for 4D matrices. However these expressions are not valid. I know I can do this combining reshape and repmat but I would like to know if there is a more compact way since there is a repelem function (I would also like to avoid using eval). Any ideas?

Réponse acceptée

Stephen23
Stephen23 le 6 Fév 2017
Modifié(e) : Stephen23 le 6 Fév 2017
It is easy to generate a comma separated list from a cell array, and use this to specify the repelem inputs:
x = 10;
C = num2cell([ones(1,ndims(A)-1),x]);
out = repelem(A, C{:})
Note that you will need to consider scalar and column vector A as special cases.
  1 commentaire
Emmanouil
Emmanouil le 6 Fév 2017
Works like a charm! I did not know I could do this with a cell array. Thanx!

Connectez-vous pour commenter.

Plus de réponses (1)

KSSV
KSSV le 6 Fév 2017
Modifié(e) : KSSV le 6 Fév 2017
Use a if condition on length(size(A)). If A is 3D your length(size(A)) will be 3 and you have to use repelem(A,1,1,x). Like wise if A is 4D, length(size(A)) will be 4.
  3 commentaires
KSSV
KSSV le 6 Fév 2017
Let it be..you can generate [1 1 x] using [ones(length(size(A))-1) x]
Emmanouil
Emmanouil le 6 Fév 2017
I know I can do this, this was my initial intention as I write in the question. The problem is that the expression repelem(A,[1,1,x]) is not valid.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Matrices and Arrays dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by