problems using newtons method

x = -2;
Tol = 0.0000001;
count = 0;
dx=1;
f=-13;
fprintf('step x dx f(x)\n')
fprintf('---- ----------- --------- ----------\n')
fprintf('%3i %12.8f %12.8f %12.8f\n',count,x,dx,f)
xVec=x;fVec=f;
while (dx > Tol || abs(f)>Tol)
count = count + 1;
fprime = cosx-x;
xnew = x - (f/fprime);
dx=abs(x-xnew);
x = xnew;
f = cosx-x;
fprintf('%3i %12.8f %12.8f %12.8f\n',count,x,dx,f)
end
this is what i was have. how can i fix this?

Réponses (1)

Walter Roberson
Walter Roberson le 19 Fév 2017

0 votes

You could define cox and cost

Catégories

En savoir plus sur Startup and Shutdown dans Centre d'aide et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by