Using ODE 45 function to solve differential equation

I have figured out how to use the Ode 45 equation using this function and it works perfectly find.

function dw_dt = equation_(t,w)

a = 5.05;

b = 2; A=1;

w(A) = a*w(A)^(0.6)-b*w(A);

when i call the function into the script

time_period = [0:.25:20];

w0 = [0.5];

[t,w] = ode45(@equation_,time_period,w0);

, this function works perfectly fine, but now I'm trying to solve for dt/dw, so the equation given, is below, so basically in trying to solve for the time given the weight and initial time of 0.

dt/dw = 1/(a*w^(.6)-b*w)

I'm not sure if the proper to right it in matlab is.

dt = 1/(a*w(1)^(.6)-b*w(1))

given that a is a=5.05 and b=2 and the w range is 0<= w <=20

how will i be able to write the call function if I'm not given a time interval,since thats what I'm trying to solve for?

[Sudarshan Kolar]

Stephanie, you can have an independent variable other than time when using ode45. You are thinking in the right direction.

function dtdw = equation2(w,t)

dtdw = 1/(a*w^(.6)-b*w);

end

[w,t] = ode45(@equation2,[0 20],[0])

In fact the documentation mentions that 't' is simply a evaluation point and y is a solution.