fsolve Finite difference - Problem: "indices must either be real positive integers or logicals"
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hello!
So I'm fairly new to matlab and I seem to run into an error I do not unterstand.
"Subscript indices must either be real positive integers or logicals."
Maybe somebody can spot my error easily?
close all;
clear all;
clc;
eta0=0;
etaInf=9;
deltaEta=0.1; %stepsize eta
N=(etaInf-eta0)/deltaEta+1; %number of nodes +1; later + number of nodes for the belt & the film ;
x0=0;
xInf=1;
deltaX=0.01; %stepsize x
M=(xInf-x0)/deltaX+1; %number of nodes x
anfangswert=horzcat(zeros(M,N),zeros(M,N),zeros(M,N)); %starting values, just zeros for now
%%Aufruf des Solvers
options=optimset('FinDiffType','central','MaxIter',10000);
Sol = fsolve(@(x)Keller_2D_Diskr_c(x(1:M,1:N),x(1:M,N+1:2*N),...
x(1:M,2*N+1:3*N),N,deltaEta,M,deltaX),anfangswert,options);
And the function:
function fval = Keller_2D_Diskr_c(f,g,H,N,deltaEta,M,deltaX)
% initialising space
fval1=zeros(M,N);fval2=zeros(M,N);fval3=zeros(M,N);
% Define functions of the Form F(X)=0
for i=1:M-1
for j=1:N-1
fval1(i,j)=((f(i,j)-f(i,j-1))/deltaEta)-g(i,j);
fval2(i,j)=((g(i,j)-g(i,j-1))/deltaEta)-H(i,j);
fval3(i,j)=((H(i,j)-H(i,j-1))/deltaEta)+f(i,j)*H(i,j)+...
2*x(i,j)*(H(i,j)*((f(i,j)+f(i,j-1)-f(i-1,j)-f(i-1,j-1))...
/2*deltaX)-g(i,j)*((g(i,j)+g(i,j-1)-g(i-1,j)-g(i-1,j-1))...
/2*deltaX));
end
end
%BC's
fval(:,1)=[-f(:,1);1-g(:,1);fval2(:,1)]; %Boundary values at eta=0
for i=2:N-1
fval(:,j)=[fval1(:,j-1);fval2(:,j);fval3(:,i-j)];
end
fval(:,N)=[fval1(:,N-1);-g(:,N);fval3(:,N-1)]; %Boundary values at eta=9
2 commentaires
Réponse acceptée
David Goodmanson
le 1 Mar 2017
Hi Max, You did not mention where in the code the error occurred, but certainly you will get such an error with
for j=1:N-1
fval1(i,j)=((f(i,j)-f(i,j-1))/deltaEta)-g(i,j); % etc.
when j=1, since the index j-1 is zero.
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Partial Differential Equation Toolbox dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!