data encryption embedding in vector

Let the

big matrix= [15 0 -50 23 0 0 75] 
small matrix=[1 0 1]
required matrix=[15 1 -50 23 0 1 75]

retaining all other values as it is

[ES]

Please explain with a small example..

say Big Matrix = [1.5, 3.5, 0, -6, 1.3]
Small Matrix = [0, 1, 1]

What would your output be?

[dpb]

Put the question itself in the space for it with a short title in the title box...as the other respondent says, an minimal example illustrating what you mean, precisely, would be helpful.

[Jatin chinchkar]

let the big matrix= [15 0 -50 23 0 0 75] small matrix=[1 0 1] required matrix=[15 1 -50 23 0 1 75]

Answer 1

[dpb]

Taking a guess, without any error checking (there would have to be a minimum of length(shorter) zero elements in the longer array to avoid an error) assuming that "encrypt the 1,0 of smaller into only in zero values of larger" means to put the values of the shorter array into the zero locations of the larger in series, that's pretty trivial--

N=numel(short);       % number in shorter
ix=long(ix==0);       % logical array of zero loc's in longer array
long(ix(1:N))=short;  % put that many elements into long at zero loc's

Perturbations of the above depending upon what other specific readings one makes of the request.

ADDENDUM

Well, the crystal ball was working this morning after all...

>> bigm=[15 0 -50 23 0 0 75];
smallm=[1 0 1];
>> bigm(bigm==0)=smallm
bigm =
  15     1   -50    23     0     1    75
>>

NB: Above IFF

length(smallm)==sum(bigm==0)

otherwise need the previous length tests/truncation/whatever for error handling.