Call variables in for loop

8 vues (au cours des 30 derniers jours)
Rok mr
Rok mr le 22 Mar 2012
Hi to all,
L1=4 L2=3 ... L30=12
for i=1:30 P(:,i)=sprintf(L%1d,i) - sprintf(L%1d,i+1) end
The result should be P(1)=L1-L2, P(2)=L2-L3, P(3)=L3-L4, P(4)=L4-L5 but it's not :) What should I use instead sprintf?
Thank you for you answers!!!

Réponse acceptée

Kevin Holst
Kevin Holst le 22 Mar 2012
To do this like you're attempting requires the use of the eval function, but be very careful in its use. Google 'eval matlab' for more information on why. And actually, the way you've got it set up wouldn't work. Your for loop needs to run from 1:29 because there's no L31.
for i = 1:29
eval(['P(' num2str(i) ')=L' num2str(i) '-L' num2str(i+1) ';'])
end
Is there any reason why your L variables aren't in a single L vector?
  7 commentaires
Kevin Holst
Kevin Holst le 22 Mar 2012
@Oleg, I haven't tried the eval(eval(eval(... suggestion, but I did evaluate char([102 108 105 112 108 114 40 39 116 105 120 101 39 41]) in my workspace... very sneaky! ;) That's the nice way to show a problem with eval. The mean way would be to "accidentally" have someone recursively remove all of the contents of their hard drive. That'd be a bad day.
Oleg Komarov
Oleg Komarov le 22 Mar 2012
Should have concealed it better...

Connectez-vous pour commenter.

Plus de réponses (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by