## plot 3D fun in x, y and z

### hend (view profile)

on 28 Mar 2017
Latest activity Commented on by KSSV

### KSSV (view profile)

on 30 Mar 2017
i want to draw a function f varied in x, y and z such that f = xyz using matlab 2014a

### KSSV (view profile)

on 28 Mar 2017

N = 10 ;
x = linspace(0,1,N) ;
y = linspace(0,1,N) ;
z = linspace(0,1,N) ;
[X,Y,Z] = meshgrid(x,y,z) ;
f = X.*Y.*Z ;
figure(1)
hold on
for i = 1:N
surf(X(:,:,i),Y(:,:,i),Z(:,:,i),f(:,:,i))
end

hend

### hend (view profile)

on 28 Mar 2017
thanks for help, but that is not a shape for the desired fn, just levels of coloured blocks as image fn not as a shape
KSSV

### KSSV (view profile)

on 28 Mar 2017
You check the ranges of x, y, z for the given function that's the shape. What you expect? Any image available? Attach it.
KSSV

### KSSV (view profile)

on 30 Mar 2017
N = 10 ;
x = linspace(0,1,N) ;
y = linspace(0,1,N) ;
z = linspace(0,1,N) ;
[X,Y,Z] = meshgrid(x,y,z) ;
F = X.*Y.*Z ;
isosurface(X,Y,Z,F,0)

### John BG (view profile)

on 28 Mar 2017

Hi hend
since your function takes in all 3 coordinates, the only way to 'see' or plot the function is slicing the volume comprised by the domain used.
For such purpose the command slice comes really handy, have a look:
N=10
range=[-N:1:N]
[x,y,z] = meshgrid(range,range,range);
v = x.*y.*z;
figure
colormap hsv
for k = range
hsp = surf(linspace(-N,N,numel(range)),linspace(-N,N,numel(range)), zeros(numel(range)) + k);
rotate(hsp,[2,-2,2],15)
xd = hsp.XData;yd = hsp.YData;zd = hsp.ZData;
delete(hsp)
slice(x,y,z,v,[-N,N],2*N,-2*N) % static volume boundaries
hold on
h1=slice(x,y,z,v,xd,yd,zd) % this is the slicing plane
hold off
view(-5,10)
axis([-10 10 -10 10 -10 10])
drawnow
colorbar
end
note the handle h1 to pull the values on the slice plane, that may be useful to extract the slicing plane points with
Xslice=h1.XData
Yslice=h1.YData
Zslice=h1.ZData
the colour bar is also useful to visualise the actual value of the function.
if you find these lines useful would you please be so kind consider marking my answer as Accepted Answer?