Problem with using isfield

3 vues (au cours des 30 derniers jours)
Veronika
Veronika le 6 Avr 2017
Réponse apportée : Jan le 6 Avr 2017
Dear all,
I have one structure with 4 fields and I would like to use function isfield for other work.
I have this part of code:
if isfield(shape,'leftLung',shape,'rightLung',shape,'spine');
tmp2 = shape.spine{1};
tmp3 = shape.leftLung{1};
tmp4 = shape.rightLung{1};
and I have this error:
Error using isfield
Too many input arguments.
Error in Newmodel (line 115)
if isfield(shape,'leftLung',shape,'rightLung',shape,'spine');
Can you please advise me, how to change this part of code for good function? Thank you for your answers.
  1 commentaire
Jan
Jan le 6 Avr 2017
The shown code has no valid Matlab syntax. Therefore the readers cannot know its intention. Suggesting a wrong idea might be more confusing then useful for you.

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Réponses (2)

Thorsten
Thorsten le 6 Avr 2017
Modifié(e) : Thorsten le 6 Avr 2017
if isfield(shape,'leftLung')
tmp3 = shape.leftLung{1};
end
if isfield(shape, 'rightLung')
tmp4 = shape.rightLung{1};
end
if isfield(shape,'spine');
tmp2 = shape.spine{1};
end
  1 commentaire
Steven Lord
Steven Lord le 6 Avr 2017
You're probably going to want to add else blocks to each of those if statements, to assign default values to tmp3, tmp4, and tmp2 if the shape struct doesn't contain fields by those names.

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Jan
Jan le 6 Avr 2017
If you have a structure with 4 fields, checking the existing of fields is not necessary. I guess:
if isfield(shape,'leftLung') && isfield(shape,'rightLung') && isfield(shape,'spine')
tmp2 = shape.spine{1};
tmp3 = shape.leftLung{1};
tmp4 = shape.rightLung{1};
end

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