Arithmetic to Functional Converter

1 vue (au cours des 30 derniers jours)
Jonathan Sullivan
Jonathan Sullivan le 26 Mar 2012
I was wondering if anyone knows of a way to convert arithmetic to functional synatx. For example, I'd like to convert the string
'a+b'
to
'plus(a,b)'
Now, this was a very simple example. It gets a bit harder with more "complicated" expressions.
'a+b.*c'
becomes:
'plus(a,times(b,c))'
I assume MATLAB already does this, under the hood somewhere. There should be a way (either documented or not) to access this. Any insights?

Réponse acceptée

Walter Roberson
Walter Roberson le 26 Mar 2012
  1 commentaire
Jonathan Sullivan
Jonathan Sullivan le 27 Mar 2012
This looks helpful. I'm going to dig into it and see if I can hack it up to suit my needs.

Connectez-vous pour commenter.

Plus de réponses (3)

owr
owr le 27 Mar 2012
Are you just trying to evaluate algebraic statements provided in string format?
If so, try "eval":
>> a = 4
a =
4
>> b = 6
b =
6
>> str = 'a+b'
str =
a+b
>> eval(str)
ans =
10
  1 commentaire
Jonathan Sullivan
Jonathan Sullivan le 27 Mar 2012
No. What I am trying to do is to change current .m files so that they use bsxfun operation instead of the traditional operations. I've found myself on several occasions, painstakingly doing this by hand. It can be quite tedious and involve a lot of time troubleshooting, especially when the code has many nested algebraic functions. It is easy to put a parenthesis in the wrong spot.
Example:
(a+b.*c.^d).*x - y.*z.^x
Becomes:
bsxfun(@minus,bsxfun(@times,bsxfun(@plus,a,bsxfun(@times,b,bsxfun(@power,c,d))),x),bsxfun(@times,y,bsxfun(@power,z,x)))
I just thought it would be nice to have a function that will do it for me.

Connectez-vous pour commenter.


John D'Errico
John D'Errico le 27 Mar 2012
Its easy, IF you look at this the right way.
First, pre-parse the expression to determine that 'a+b.*c' has three variables in it, a, b, and c. Define objects a, b and c. Now overload the plus and times operators to actually use bsxfun.
Finally, let MATLAB do the operation, using an eval. You CAN make this work, but you will need to be careful and think it out.
  1 commentaire
Jonathan Sullivan
Jonathan Sullivan le 27 Mar 2012
Yea. I'm aware that I can overload the functions and it'll work. But I'd like it to be stand alone. I tend to port my code over to may different people across many different machines. I would prefer to not have to define new objects and overload these functions on all their machines.

Connectez-vous pour commenter.


anisa
anisa le 31 Mai 2012
Hi, Did you manage to find a method in MATLAB that already implements this. I am trying to do the same thing I am sure that somewhere in matlab there should already be a method. If you could let me know that would be greatly appreciated.
  1 commentaire
Walter Roberson
Walter Roberson le 31 Mai 2012
I, on the other hand, am "sure" that there is no documented MATLAB method to do this (other than what John outlined.)

Connectez-vous pour commenter.

Catégories

En savoir plus sur Data Type Identification dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by