How to replace the diagonal elements of a matrix with 0 fro avoiding self loops?
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SUNANNA S S
le 19 Avr 2017
Commenté : tommsch
le 28 Juin 2024 à 8:33
I have a matrix
M= 1 0 0 0 1 0
0 1 0 1 0 0
0 0 1 0 1 1
1 0 0 1 0 0
1 1 1 0 0 0
0 0 0 1 0 1
I want to replace all the diagonal elements in this matrix to 0 if it is 1.
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Ramtin Nazerian
le 21 Déc 2022
Out = M.*-(eye(height(M))-1);
This will make all the diagonal values of your matrix zero as long as the matrix is square. hope that helps :).
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Plus de réponses (3)
Stephen23
le 19 Avr 2017
Modifié(e) : Stephen23
le 19 Avr 2017
Method one: indexing:
M(1:1+size(M,1):end) = 0
Method two: eye:
M.*~eye(size(M))
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Stephen23
le 19 Avr 2017
A strict interpretation of the question requires only diagonals equal to one get changed to zero: this is easy to implement with eye:
M.*~(eye(size(M)) & M==1)
Roger Stafford
le 19 Avr 2017
If your matrix M is not square and if you only want those diagonal elements changed to zero “if it is 1”, then you can do the following. Other diagonal elements not equal to one will remain unchanged. (Your description was perhaps a little ambiguous on this latter point.)
[m,n] = size(M);
d = 1:m+1:min(m^2,m*(n-1)+m);
f = find(M(d))==1;
M(d(f)) = 0;
4 commentaires
Zeina Abdullah
le 5 Jan 2022
@Stephen can you help me by try to answer the last question in my profile please
Christine Tobler
le 23 Mai 2017
Modifié(e) : Christine Tobler
le 23 Mai 2017
If you are using the graph/digraph classes, you can also tell the constructor not to insert any self-loops for the diagonal elements:
g = graph(A, 'omitSelfLoops');
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