Finding series of repeating numbers in matrix

10 vues (au cours des 30 derniers jours)
Michael Saniuk
Michael Saniuk le 13 Mai 2017
Commenté : Michael Saniuk le 13 Mai 2017
Hello, I am trying to find begginings and endings of repeating zeros in matrix, eg: for input matrix:
1 0 0 0 0 0 1 1 0 0 1 1 1 0 0 0 0 0 1 1 0 0 0 1 0 0 1
I want to get:
beggining = [2 9 14 21 25]
ending = [6 10 18 23 26]
Does anyone know how to do it?

Réponse acceptée

Stephen23
Stephen23 le 13 Mai 2017
Modifié(e) : Stephen23 le 13 Mai 2017
>> V = [1,0,0,0,0,0,1,1,0,0,1,1,1,0,0,0,0,0,1,1,0,0,0,1,0,0,1];
>> D = [V(1)==0,diff(V==0)];
>> find(D>0)
ans =
2 9 14 21 25
>> find(D<0)-1
ans =
6 10 18 23 26

Plus de réponses (1)

Guillaume
Guillaume le 13 Mai 2017
v = [1 0 0 0 0 0 1 1 0 0 1 1 1 0 0 0 0 0 1 1 0 0 0 1 0 0 1]
beginning = strfind([1 v], [1 0])
ending = strfind([v 1], [0 1])
Despite its name, strfind works with sequence of numbers as well.
  1 commentaire
Michael Saniuk
Michael Saniuk le 13 Mai 2017
wow, this works too ^^ thank you

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