structure to array

I'm looking to write values stored in an structure to an array like this:

p_start = 20;
p_end = 400;
p_diff = p_end - p_start;
x = 1;

s.test1 = zeros(p_diff,1);
s.test2 = zeros(p_diff,1);
s.test3 = cell(p_diff,1);
t_array = cell(p_diff,3);

for i=p_start:1:p_end
t_array(x,:) = {s.test1(i) s.test2(i) s.test3.(i)};
x = x+1;
end

is it possible to fill t_array without having to go through a loop?

Thanks for your help!

Answer 1

[Oleg Komarov]

In this case no, and you have to use:

for i = 1:p_diff
    t_array(i,:) = {s.test1(i) s.test2(i) s.test3{i}};
end

If you try to describe why are you creating test1 and test2 etc... and what you wanna do next we can try to come up with loopless solution.