delete elements from a cell array
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elisa ewin
le 21 Juin 2017
Modifié(e) : Andrei Bobrov
le 22 Juin 2017
Hi!
I have a cell array b (attached); in each cell of b I have an expression like this: 'Weather booming Chilli Relax https://t.co/pwp00Ndw3d' or expressions with @,#,$. I want to delete from these expressions all the characters like @,#,$ and the links like https://t.co/pwp00Ndw3d.
Example: if I have 'Weather booming @Chilli Relax# https://t.co/pwp00Ndw3d', I will want it becames 'Weather booming Chill Relax'
Can you help me? thanks
3 commentaires
Jan
le 22 Juin 2017
Modifié(e) : Jan
le 22 Juin 2017
Weather booming Chilli Relax https://t.co/pwp00Ndw3d
Perhaps I'm too distrustful, but I've modified the URL slightly to be sure. This does not change the core of the question or the answer. Sorry, these are hard times in the world wide web. Please do not take this personally.
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Andrei Bobrov
le 22 Juin 2017
regexprep(b,'[$#@]|\<https:/+\S*\>','')
8 commentaires
Andrei Bobrov
le 22 Juin 2017
Modifié(e) : Andrei Bobrov
le 22 Juin 2017
Hi Jan! Yes! "Russian rocket". :)
regexprep(b,'\<[^A-Za-z \?\,]|https:/+\S*\>','')
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Jan
le 22 Juin 2017
Modifié(e) : Jan
le 22 Juin 2017
S = 'Weather booming Chilli Relax https://t.co/pwp00Ndw3d';
C = strsplit(S, ' ');
C(contains(C, '/')) = []; % Or how you identify a link
for iC = 1:numel(C)
aC = C{iC};
C{iC} = aC(isstrprop(aC, 'alphanum'));
end
Result = sprintf('%s ', C{:});
Result(end) = [];
The command contains was introduced in R2016b. If you have an older version, use:
function Tf = contains(C, Patterm)
Tf = ~cellfun('isempty', strfind(C, Pattern));
end
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