Effacer les filtres
Effacer les filtres

Plotting a graph using indexed values

14 vues (au cours des 30 derniers jours)
Christine Nee
Christine Nee le 21 Juil 2017
Commenté : Christine Nee le 24 Juil 2017
I am trying to generate a plot. I use Max_value_Force and Min_value_Force to find the max and min values then I find where they are indexed. I then take the index and go back to my data and find when the force was min and max. After that I want to plot ALL the values between the max and min times as a plot with time (t) vs force (f). The reason why I am experimenting with time for now is because I am trying to figure out what full cycles look like on something I am analyzing. when I run this code I get an error.
[Max_value_force,I] = max(f(:))
Time_Max_Force = t(I)
[Min_value_force,I] = min(f(:))
Time_Min_Force = t(I)
plot(t(Time_Min_Force:Time_Max_Force),f(Time_Min_Force:Time_Max_Force))
"Warning: Integer operands are required for colon operator when used as index "
How do I get this to successfully generate a plot

Réponses (1)

Jess Lovering
Jess Lovering le 21 Juil 2017
It looks like you are trying to use the max and min values as the indices instead of the index values. See example:
[Max_value_force,maxI] = max(f(:))
Time_Max_Force = t(maxI)
[Min_value_force,minI] = min(f(:))
Time_Min_Force = t(minI)
plot(t(minI:maxI),f(minI:maxI))
  1 commentaire
Christine Nee
Christine Nee le 24 Juil 2017
Doesn't entirely work.
So here is my code. I am unable to plot nor put into array those values. I get an error with your revised code and my original code:
%Finding max values and creating a seperate array
[Max_Value_Force,maxI] = max(f(:))
Time_Max_Force = t(maxI)
%Max_Value_Force_Times_Array = t(I+1)
[Min_Value_Force,minI] = min(f(:))
Time_Min_Force = t(minI)
%Create the table with those values
%table has alternating values
Table = [Max_Value_Force Time_Max_Force; Min_Value_Force Time_Min_Force]
plot(t(minI:maxI),f(minI:maxI))
Any ideas on how to get this working as a plot and also on a table?

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