How to extract every elements with different dimension at multiple cells in efficient manner?

1 vue (au cours des 30 derniers jours)
Dear all,
Say I have three cells, where the element
dd = [49;50;51;52;53;54] [55;56;57] [85;86;87;88;89;90]
The objective is to extract all the element in each cell and make it into single row, such that
[40 50 51 52 53 54 55 56 57 85 86 87 88 89 90]
I used the following lines.
C =1
for i =1:size(dd,2)
Xcx = cell2mat (dd (1,i));
ee =[]
ee (1,1: length (Xcx)) =Xcx;
for k =1: length (ee )
new (C,1) = ee (k)
C =C+1
end
end
Even though the code do the trick, I am looking if there is more advance and compact ways of doing it?
Thanks in advance

Réponse acceptée

balandong
balandong le 3 Août 2017
Modifié(e) : balandong le 3 Août 2017
Dear Akira, Thanks for your response, I give an idea of using the VERTCAT. Using VERTCAT instead of HORZCAT skip the need of CELLFUN and TRANSPOSE.
dd = {[49;50;51;52;53;54], [55;56;57], [85;86;87;88;89;90]};
output1 =vertcat (dd{:});
Thanks for your answer, however I had to accept this solution as a better and more compact ways.

Plus de réponses (2)

Sanjay Nair
Sanjay Nair le 2 Août 2017
Hello,
If I'm understanding your problem correctly you have a cell array that can be defined in the following manner
dd = {[49;50;51;52;53;54], [55;56;57], [85;86;87;88;89;90]};
Since you have a cell array of column vectors with only three elements, perhaps the easiest way to extract them into a single row vector would be to transpose and concatenate the contents in a single command as follows:
row = [dd{1}', dd{2}', dd{3}'];
You can get more information about accessing data in cell-arrays in: https://www.mathworks.com/help/matlab/matlab_prog/access-data-in-a-cell-array.html
  1 commentaire
balandong
balandong le 3 Août 2017
HI Sanjay, Thanks for your response and idea. Your suggestion maybe effecient for few cell arrays. However, I want to generalize the code so that it can handle many cell array, say, > 20 cell arrays. I dont think it is a godd practice to do as following
row = [dd{1}', dd{2}', dd{3}', dd{4}', dd{5}', dd{6}', dd{7}', dd{8}', dd{9}', dd{10}', dd{11}', dd{12}', dd{13}', dd{14}', dd{15}', dd{16}', dd{17}', dd{18}', dd{19}', dd{20}'];

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Akira Agata
Akira Agata le 3 Août 2017
How about using cellfun and horzcat functions as follows. In this code, each element in cell array dd is transposed by cellfun. Next, horzcat concatenate each element horizontally.
dd = {[49;50;51;52;53;54], [55;56;57], [85;86;87;88;89;90]};
ddTrans = cellfun(@transpose,dd,'UniformOutput',false);
Output = horzcat(ddTrans{:});
  1 commentaire
balandong
balandong le 3 Août 2017
HI Akira, I really appreciate the time and idea you provide. Your suggestion work like a charm. Thank you

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