Vectorization

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Aravin
Aravin le 15 Avr 2012
Dear Community,
Let say I have Matrix M. In Matrix M, each Column is feature of Image. Now what I want to get a binary matrix B by following way.
for given image feature i:
B(1,i) = M(1,i) >= M(2,i);
its mean for each image feature, each cell is compared to its next cell. I want to do it without loops for speed.
  1 commentaire
Oleg Komarov
Oleg Komarov le 15 Avr 2012
"Without loops for speed" is really not the right statement anymore.
Many times loops are much faster is correctly set up.

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Réponse acceptée

Oleg Komarov
Oleg Komarov le 15 Avr 2012

Plus de réponses (1)

Jan
Jan le 15 Avr 2012
B = (M(1:end-1, :) >= M(2:end, :));
  2 commentaires
Jan
Jan le 15 Avr 2012
It is worth to investigate the similarities and differences to Oleg's (faster) solution.
Aravin
Aravin le 18 Avr 2012
Jan, Oleg worked on my small examples. I could find any dissimilarity. If you have in your mind then please share.
Thanks for your help too.

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