Algorithm conversion with code generation

3 vues (au cours des 30 derniers jours)
Chan KitHoe
Chan KitHoe le 16 Sep 2017
Commenté : Image Analyst le 17 Sep 2017
Hi all, I am working on an algorithmic function and I'd like to convert it into C. Code as stated below,
ImgR= Input(:,:,1); % Red colour channel.
ImgG= Input(:,:,2); % Green colour channel.
ImgB= Input(:,:,3); % Blue colour channel.
However while converting, I ran into an error stating - "Index expression out of bounds. Attempted to access element 2. The valid range is 1-1." How can I resolve this issue? Thanks!

Réponses (1)

John D'Errico
John D'Errico le 16 Sep 2017
You don't have a color image. You have a purely grayscale image. So trying to extract the red green and blue planes is waste of time.
So you need to convert the grayscale image to three channel color, most simply done by replicating the gray image into three color planes, or use an appropriate tool to do a better job. Or work with a color image to start with.
  3 commentaires
Walter Roberson
Walter Roberson le 17 Sep 2017
if ndims(Input) > 2
ImgR= Input(:,:,1); % Red colour channel.
ImgG= Input(:,:,2); % Green colour channel.
ImgB= Input(:,:,3); % Blue colour channel.
else
ImgR = Input;
ImgG = Input;
ImgB = Input;
end
Image Analyst
Image Analyst le 17 Sep 2017
Even though MATLAB is case sensitive, I don't think it's a good idea to name variables after built-in functions, even if the capitalization is different.

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