I have 3D matrix A=50x60x180 and I want subtract B=50x60 to get same size C=50x50x180? Can anybody use for loop to do this operation?

2 commentaires

C = zeros(50,60,180);
for i = 1:180
C(:,:,i) = A(:,:,i) - B;
end
Is this what you mean?
Andrei Bobrov
Andrei Bobrov le 21 Sep 2017
?
size of the C -> [50x 50 x180]? Maybe - [50x 60 x180]

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 Réponse acceptée

Andrei Bobrov
Andrei Bobrov le 21 Sep 2017

1 vote

C = A - B;
or
C = bsxfun(@minus,A,B);

2 commentaires

Walter Roberson
Walter Roberson le 21 Sep 2017
The first of those works in R2016b or later but not in earlier versions.
Andrei Bobrov
Andrei Bobrov le 21 Sep 2017
Walter! I am agree with you!

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