How to display the elements of a matrix D as an input for the next matrix 729x729 rows and columns?
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surabhi sachdeva
le 3 Oct 2017
Modifié(e) : surabhi sachdeva
le 6 Oct 2017
I want the matrix elements to be inputted in the rows as well as in the columns of the matrix so as to get 729x729 matrix.
I am attaching the 729x6 matrix whose elements I want to show as input in the rows and columns.
Please help me generate the 729x729 matrix this way using MATLAB.
regards
surabhi
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Azzi Abdelmalek
le 3 Oct 2017
Your question is not clear. you have a 729x6 matrix, if you want a 729x729 you have to define the missing data
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Walter Roberson
le 3 Oct 2017
As discussed in https://www.mathworks.com/matlabcentral/answers/359051-how-to-display-729-double-input-arguments-in-tabular-form-to-get-729-729-matrix#comment_489118 it is important information that you are using R2013a and that you do have access to the Statistics toolbox. I asked you there whether you needed this for display purposes or only for computation purposes, and I showed you there how best to do this for computation purposes.
For display purposes, you will need a display that is a minimum of 36450 pixels wide, assuming that you are willing to accept 8 pixels per character including intra-character gap (narrower characters are hard to read; 6 pixels per character is considered barely readable.) This calculation assumes a 2 pixel gap between labels, which is quite tight.
To draw this, you would text() every character into place, having set the FontSize property to be quite small, and having set a monospaced font. To avoid having space take up a full character position, you would have to text() every column individually, but at least you can do an entire column at a time instead of having to do each item individually.
If someone is imposing on you a need to use a datastructure that looks sort of like this when it displays, then in R2007a to R2013a with Statistics Toolbox, you would use
H = cellstr( strcat('T', char('0' + fullfact([3 3 3 3 3 3])-1 ) ) );
emptyvals = repmat({''}, length(H), length(H));
YourTable = cell2dataset(emptyvals, 'ReadVarNames', false, 'ReadObsNames', false, 'VarNames', H, 'ObsNames', H);
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Walter Roberson
le 4 Oct 2017
I already showed you in the previous Question how to convert the 729 x 6 to 729 x 729: use the 12 dimensional array.
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OCDER
le 3 Oct 2017
Maybe you can make your own data structure and get/set methods to access them by 6-tuple char:
Tuple = fullfact([3 3 3 3 3 3]) - 1;
List = cell(729, 1);
for j = 1:numel(List)
List{j} = sprintf('%d%d%d%d%d%d', Tuple(j, :));
end
List = %Your list of 6-tuple names, cell array of char. Your row and column names.
729×1 cell array
'000000'
'100000'
'200000'
'010000'
'110000'
'210000'
....
M = zeros(length(List)); %Your 729x729 matrix
M = setM(M, List, '000000', '100000', 2) %To access a row and col in M by 6-tuple string and set to 2
M =
0 2 0 0 0 0
0 0 0 0 0 0
0 0 0 0 0 0
0 0 0 0 0 0
0 0 0 0 0 0
0 0 0 0 0 0
V = getM(M, List, '000000', '100000') %to access M based on a row and col 6-tuple strings
V =
2
But you'll need these 2 functions:
%Set a value in M based on tuple
function M = setM(M, List, RowStr, ColStr, Value)
Row = contains(List, RowStr);
Col = contains(List, ColStr);
M(Row, Col) = Value;
end
%Get a value in M based on tuple
function Value = getM(M, List, RowStr, ColStr)
Row = contains(List, RowStr);
Col = contains(List, ColStr);
Value = M(Row, Col);
end
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