Use fprintf to create a multiplication table.

Create a multiplication table from 1 to 13 for the number 6. Your table should look like this.

1 times 6 is 6 2 times 6 is 12 3 times 6 is 18 . . .

Answer 1

[Paulo Silva]

clc
Start=6;
Stop=6;
for u=Start:Stop;
    for v=1:13;
        fprintf('%d times %d is %d\n',u,v,u*v)
    end
    fprintf('\n')
end

The code works for more than what is requested, for example create several multiplication tables

clc
Start=1;
Stop=10;
for u=Start:Stop;
    for v=1:10;
        fprintf('%d times %d is %d\n',u,v,u*v)
    end
    fprintf('\n')
end

Simple version for just what is requested

 clc
 for v=1:13
  fprintf('%d times %d is %d\n',6,v,6*v)
 end

[Walter Roberson]

Paulo, as this was obviously a homework question, it is a good thing that you left in a deliberate bug.

Answer 2

[Mohamed Bireir]

clc

v=1:1:13;
u=6.*v;
table=[v;u]
fprintf('%d times %d is %d\n',6,v,6*v)

[Walter Roberson]

6 times 1 is 2
3 times 4 is 5
6 times 7 is 8
9 times 10 is 11
12 times 13 is 6
12 times 18 is 24
30 times 36 is 42
48 times 54 is 60
66 times 72 is 78

I don't think that is the required output...

Answer 3

[van exel vispo]

This should work better

n = 1:13;
m = n.*6;
table = [n;m]
fprintf('%d times 6 is %d \n',table)

Answer 4

[Walter Roberson]

See the examples in the fprintf documentation.

Answer 5

[Alexander Pollock]

How to do this without using loops ? for example if and else statements ?

[Walter Roberson]

Suppose you want to print a table with three columns of values, with the value stored in c1, c2, c3. Without assuming that c1, c2, c3 are currently stored as columns, you can construct

C = [c1(:), c2(:), c3(:)];

and now C is a something by 3 array of values to be output.

Now here comes the trick:

fprintf('text for first goes here %f text for second goes here %f text for third goes here %f\n', C.' );  %notice the transpose