Passing function handle to another function and assigning varying number of input arguments to it

Hi,

I am trying to write a code in which I need to pass a handle function to another function, let say

   function b=myfun1(a)
   b=2*a;
   end

   function b=myfun2(handle_f,a)
   b=a*handle_f(a)
   end

   result=myfun2(@(aa)myfun1(aa),a);

Well, this works perfectly fine. Now let say that I want to decide to vary the number of and type of arguments of myfun1 or use completely different function. How should I write myfun2 to be able to work with any type of function with different number of input arguments and of course same output type?

Answer 1

[Andrei Bobrov]

please read about varargin, nargin and varargout, nargout

eg

function b=myfun2(handle_f,varargin)
   a = varargin{1};
   b=a.*handle_f(varargin{:})
end

on Hossein's comment

myfun2(@(x)myfun3(x,y),a); %here y is defined
myfun2(@(y)myfun3(x,y),a); %here x is defined
myfun2(@(x,y)myfun3(x,y),a,y);
myfun2(@(y,x)myfun3(x,y),a,x);

[Hossein]

Hi,

Thanks, I think I am getting there. Now how do I pass @(x,y)myfun3(x,y) as argument and then assign a and b to myfun3?

myfun2(@(x,y)myfun3(x,y),a);

[Andrei Bobrov]

myfun2(@(x)myfun3(x,y),a); %here y is defined

or

myfun2(@(y)myfun3(x,y),a); %here x is defined