loadind data loop fastly?
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Hi everybody, Please i have this code that load data too long time, i want to read it fastly(reduce time execution), somebody can i help me?
%Data is the 381x247x3 matrix; if true
LastGood = floor((122.5 - 50) / Header.Fstep) + 1 - 1; % value =29
FirstGood = ceil((140 - 50) / Header.Fstep) + 1 + 1; % value =38
disp(LastGood); % value =29
disp(FirstGood); % value =38
disp(size(Data, 2)); % value =247
for(k = 1:size(Data, 2))
InterpolazioneReale1 = fit(cat(2,[1:LastGood],[FirstGood:381])',cat(1,real(Data(1:LastGood,k,1)),real(Data(FirstGood:end,k,1))),'splineinterp');
InterpolazioneReale2 = fit(cat(2,[1:LastGood],[FirstGood:381])',cat(1,real(Data(1:LastGood,k,2)),real(Data(FirstGood:end,k,2))),'splineinterp');
InterpolazioneReale3 = fit(cat(2,[1:LastGood],[FirstGood:381])',cat(1,real(Data(1:LastGood,k,3)),real(Data(FirstGood:end,k,3))),'splineinterp');
InterpolazioneImmaginaria1 = fit(cat(2,[1:LastGood],[FirstGood:381])',cat(1,imag(Data(1:LastGood,k,1)),imag(Data(FirstGood:end,k,1))),'splineinterp');
InterpolazioneImmaginaria2 = fit(cat(2,[1:LastGood],[FirstGood:381])',cat(1,imag(Data(1:LastGood,k,2)),imag(Data(FirstGood:end,k,2))),'splineinterp');
InterpolazioneImmaginaria3 = fit(cat(2,[1:LastGood],[FirstGood:381])',cat(1,imag(Data(1:LastGood,k,3)),imag(Data(FirstGood:end,k,3))),'splineinterp');
Data(LastGood + 1:FirstGood - 1,k,1) = InterpolazioneReale1(LastGood + 1:FirstGood - 1) + i * InterpolazioneImmaginaria1(LastGood + 1:FirstGood - 1);
Data(LastGood + 1:FirstGood - 1,k,2) = InterpolazioneReale2(LastGood + 1:FirstGood - 1) + i * InterpolazioneImmaginaria2(LastGood + 1:FirstGood - 1);
Data(LastGood + 1:FirstGood - 1,k,3) = InterpolazioneReale3(LastGood + 1:FirstGood - 1) + i * InterpolazioneImmaginaria3(LastGood + 1:FirstGood - 1);
end
end
6 commentaires
per isakson
le 10 Oct 2017
Modifié(e) : per isakson
le 10 Oct 2017
Make a minimal working example, MWE. This MWE should focus one your question.
We cannot run your m-files without the m-files called, data files and furthermore we don't know what speed you expect.
KSSV
le 10 Oct 2017
It depends on what data your text file has....post your text file....to get help.
per isakson
le 10 Oct 2017
Modifié(e) : per isakson
le 10 Oct 2017
"loadind data loop fastly" How do you currently load/read the data files? Your way might be as fast as it gets.
Rik
le 10 Oct 2017
Sometimes you can even wee it in task manager: if your disk load is 100%, further optimizing your code will not yield any benefit.
Note:
cat(2,[1:LastGood],[FirstGood:381])'
can be simplified to:
[1:LastGood, FirstGood:381]'
Then store this in a variable instead of creating it 6 times.
Performing 6 spline fits for the same locations seems rather inefficient. Could this be simplified?
denis bertin
le 10 Oct 2017
Modifié(e) : denis bertin
le 10 Oct 2017
Réponse acceptée
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