Effacer les filtres
Effacer les filtres

How can I sort my data by within a sorting

3 vues (au cours des 30 derniers jours)
John Hunt
John Hunt le 10 Oct 2017
Modifié(e) : dpb le 10 Oct 2017
I have a set of x,y,z data. I want to have all of the data sorted by x (least to greatest), then I want to have the y data be sorted within the x sort (least to greatest in the positive x data and then least to greatest for the negative data). I then want to do the same in the same for the z data in the positive and negative y data. How can I do that?
  1 commentaire
John Hunt
John Hunt le 10 Oct 2017
The answers below are almost what I need, this sorts the data by the last column, so I have positive number with negative numbers in the -x numbers. I need them separate.
so -x,y -x,-y -x,-y -x,-y -x,y x,y x,-y x,-y x,y x,y to --> -x,-y -x,-y -x,-y -x,y -x,y x,-y x,-y x,y x,y x,y

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Réponses (2)

Cedric
Cedric le 10 Oct 2017
[xyz_sorted, id] = sortrows( [x(:),y(:),z(:)] ) ;
  3 commentaires
Cedric
Cedric le 10 Oct 2017
You will have to make a numeric example.
dpb
dpb le 10 Oct 2017
Ewww...that's taking some doing but isn't too bad; just bookkeeping.
  1. sort x keeping index vector, iSrt
  2. get logical vector for y of negative locations, iNegY
  3. build sorted row in pieces of [x(iSrt(iNegY)) y(iNegY)]
  4. concatenate the remainder with [x(iSrt(~iNegY)) y(~iNegY)]
Is then complicated that there's the subsequent partitioning of Z as subset of Y to keep those pieces so in reality there's four subsections, not just two (or, of course, if you also mean this for X, then it's 8).
I've got another appointment at moment, but that's the idea...

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dpb
dpb le 10 Oct 2017
Modifié(e) : dpb le 10 Oct 2017
doc sortrows
Following up on previous note -- given
>> x=rand(10,1); y=rand(size(x))-0.5;
>> [x y]
ans =
0.1576 0.1557
0.9706 -0.4643
0.9572 0.3491
0.4854 0.4340
0.8003 0.1787
0.1419 0.2577
0.4218 0.2431
0.9157 -0.1078
0.7922 0.1555
0.9595 -0.3288
>>
for the x,y case
>> [~,iSrt]=sort(x);
>> iNegY=y<0;
>> [sortrows([x(iSrt(iNegY)) y(iNegY)]); ...
sortrows([x(iSrt(~iNegY)) y(~iNegY)])]
ans =
0.1576 -0.4643
0.9572 -0.1078
0.9706 -0.3288
0.1419 0.1557
0.4218 0.3491
0.4854 0.4340
0.7922 0.1787
0.8003 0.2577
0.9157 0.2431
0.9595 0.1555
>>
Presuming that's the desired result, have to subsequently partition z by the two subsections within y for total of four pieces.

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