Calculating exact roots of 6th degree polynomial

5 vues (au cours des 30 derniers jours)
Deepayan Bhadra
Deepayan Bhadra le 18 Oct 2017
I've a fat 6x6 matrix E with symbolic variables. I'm trying to compute sqrt(eig(E'E)), ie, the singular values. The answer begins with 'root( ) etc. How do I get MATLAB to solve this 6th degree polynomial and show me more pleasing answers? Thanks a lot.

Réponses (1)

Image Analyst
Image Analyst le 19 Oct 2017
Use roots(), not root().
  3 commentaires
Walter Roberson
Walter Roberson le 19 Oct 2017
root() is the placeholder that replaced RootOf() a couple of releases ago in the Symbolic Toolbox.
Walter Roberson
Walter Roberson le 19 Oct 2017
Modifié(e) : Walter Roberson le 19 Oct 2017
Which Galois group does it belong to? Because it is not generally possible to solve for exact algebraic roots.
By the way, have you ever looked at how long the roots are just for quartics? About 12500 characters per solution when using bare symbols for the coefficients; much much longer if the coefficients are expressions as you imply is happening for you.
Suppose you managed to find a (say) million character closed form for one of your eigenvalues: realistically, what would you do with it?

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