This assignment writes a 'char' value into a 'double' type.
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if true function word = fcn(L,Ne,re,templates) word = []; for n=1:Ne [r,c] = find(L==n); % Extract letter n1=re(min(r):max(r),min(c):max(c)); % Resize letter (same size of template) img_r=imresize(n1,[42 24]); comp=[ ]; for n=1: 24 : 240 sem=Corr2(templates(1:42,n:n+23),img_r); comp=[comp sem]; end vd=find(comp==max(comp)); %*-*-*-*-*-*-*-*-*-*-*-*-*- if vd==1 letter='1'; elseif vd==2 letter='2'; elseif vd==3 letter='3'; elseif vd==4 letter='4'; elseif vd==5 letter='5'; elseif vd==6 letter='6'; elseif vd==7 letter='7'; elseif vd==8 letter='8'; elseif vd==9 letter='9'; else letter='0'; end
% Letter concatenation
word = [word letter]; end
end end i use the matlab code on simulink but show the error!
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Rik
le 19 Oct 2017
You should change various things. See the version below.
function word = fcn(L,Ne,re,templates)
%initializing to empty char can be done with word='';
word = char(zeros(1,Ne));
for n=1:Ne
[r,c] = find(L==n);
% Extract letter
n1=re(min(r):max(r),min(c):max(c));
% Resize letter (same size of template)
img_r=imresize(n1,[42 24]);
comp=zeros(1,10);%explicit pre-allocation
for m=1: 24 : 240%conflicted index, also changed to m on next line
sem=Corr2(templates(1:42,m:m+23),img_r);
comp((m+23)/24)=sem;
end
vd=find(comp==max(comp));
%*-*-*-*-*-*-*-*-*-*-*-*-*-
letter=sprintf('%d',mod(vd,10));
%mod(vd,10) keeps 1:9 the same and changes 10 to 0.
% Letter concatenation
word(n) = letter;
end
2 commentaires
Rik
le 19 Oct 2017
The only differences between my function and yours, is that mine is more compact, should be a tiny bit faster, doesn't overwrite n in the second loop, and returns a char vector instead of a double vector.
If you can use your function, you can also use mine. I hardly ever use Simulink at all, so I don't understand your question and can't answer it.
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