Hi; Can you help me to find fault in my code?

Write a function called sort3 that takes a 3-element vector as its sole arguments. It uses if-statements, possibly nested, to return the three elements of the vector as three scalar output arguments in nondecreasing order, i.e., the first output argument equals the smallest element of the input vector and the last output argument equals the largest element. NOTE: Your function may not use any built-in functions, e.g., sort, min, max, median, etc.

My code;

function [s1 s2 s3] = sort3(V)
    a = V(1), b = V(2), c = V(3);
    if a<=b && a<=c
        s1 = a;
        if b<=c
            s2 = b;
            s3 = c;
        else
                s2=c;
                s3=b;
                end
    else if b<=a && b<=c
            s1=b;
            if a<=c
                s2=a;
                s3=c;
            else
                s2=c;
                s3=a;
            end
    else c<=b && c<=a
        s1=c;
        if b<=a
            s2=b;
            s3=a;
        else 
            s2=a;
            s3=b;
        end
    end

The fault;

>> [s1 s2 s3] = sort3([4 18 3])
Error: File: sort3.m Line: 3 Column: 5
At least one END is missing: the statement may begin here.

I dont understand this fault.

[Walter Roberson]

Please do not close questions that have answers.

Answer 1

[KSSV]

Type end at the end of the file.....

Answer 2

[Walter Roberson]

Count nesting:

function [s1 s2 s3] = sort3(V)
    a = V(1), b = V(2), c = V(3);
    if a<=b && a<=c                %enter nesting 1
        s1 = a;
        if b<=c                    %enter nesting 2
            s2 = b;
            s3 = c;
        else                       %continue nesting 2
                s2=c;
                s3=b;
                end                %end nesting 2, resume nesting 1
    else if b<=a && b<=c           %continue nesting 1 with "else", enter nesting 2 with "if"
            s1=b;
            if a<=c                %enter nesting 3
                s2=a;
                s3=c;
            else                   %continue nesting 3
                s2=c;
                s3=a;
            end                    %end nesting 3, resume nesting 2
    else c<=b && c<=a              %continue nesting 2 with "else". Print out the result of "c<=b && c<=a" because there is no "if" statement here
        s1=c;
        if b<=a                    %enter nesting 3
            s2=b;
            s3=a;
        else                       %continue nesting 3
            s2=a;
            s3=b;
        end                        %end nesting 3, resume nesting 2
    end                            %end nesting 2, resume nesting 1

                                     %uh-oh, we are at end of routine and still in nesting 1!

Please review "else if" compared to "else if"

Answer 3

[Vignesh M]

   function [u1,u2,u3] = sort3(v)

if v(1) <= v(2) && v(2) <= v(3);

      u1=v(1);u2=v(2);u3=v(3);
  elseif v(1) <= v(3) && v(3) <= v(2);
      u1=v(1);u2=v(3);u3=v(2);
  elseif v(2) <= v(1) && v(1) <= v(3);
      u1=v(2);u2=v(1);u3=v(3);
  elseif v(2) <= v(3) && v(3) <= v(1);
      u1=v(2);u2=v(3);u3=v(1);
  elseif v(3) <= v(1) && v(1) <= v(2);
      u1=v(3);u2=v(1);u3=v(2);
  else v(3) <= v(2) && v(2) <= v(1);
      u1=v(3);u2=v(2);u3=v(1);
  end
    end

Answer 4

[Dong Chen]

function [x y z] = sort3(m)

x = m(1);
y = m(2);
z = m(3);

if (x>y)
    t = x;
    x = y;
    y = t;
end

if (x>z)
    t = z;
    z = x;
    x = t;
end

if (y>z)
    t = y;
    y = z;
    z = t;  
end