sine wave plot
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Hi,
I am having some trouble plotting a sine wave and i'm not sure where i am going wrong.
i have
t = [0:0.1:2*pi]
a = sin(t);
plot(t,a)
this works by itself, but i want to be able to change the frequency. When i run the same code but make the change
a = sin(2*pi*60*t)
the code returns something bad. What am i doing wrong? How can i generate a sin wave with different frequencies?
14 Comments
Gokul Krishna N
on 13 Oct 2021
Just been reading the comments in this question. Hats off to you, sir @Walter Roberson
Accepted Answer
Rick Rosson
on 24 Apr 2012
Please try:
%%Time specifications:
Fs = 8000; % samples per second
dt = 1/Fs; % seconds per sample
StopTime = 0.25; % seconds
t = (0:dt:StopTime-dt)'; % seconds
%%Sine wave:
Fc = 60; % hertz
x = cos(2*pi*Fc*t);
% Plot the signal versus time:
figure;
plot(t,x);
xlabel('time (in seconds)');
title('Signal versus Time');
zoom xon;
HTH.
Rick
10 Comments
More Answers (9)
Junyoung Ahn
on 16 Jun 2020
clear;
clc;
close;
f=60; %frequency [Hz]
t=(0:1/(f*100):1);
a=1; %amplitude [V]
phi=0; %phase
y=a*sin(2*pi*f*t+phi);
plot(t,y)
xlabel('time(s)')
ylabel('amplitude(V)')
2 Comments
Robert
on 28 Nov 2017
aaa,
What goes wrong: by multiplying time vector t by 2*pi*60 your discrete step size becomes 0.1*2*pi*60=37.6991. But you need at least two samples per cycle (2*pi) to depict your sine wave. Otherwise you'll get an alias frequency, and in you special case the alias frequency is infinity as you produce a whole multiple of 2*pi as step size, thus your plot never gets its arse off (roundabout) zero.
Using Rick's code you'll be granted enough samples per period.
Best regs
Robert
0 Comments
shampa das
on 26 Dec 2020
Edited: Walter Roberson
on 31 Jan 2021
clc; t=0:0.01:1; f=1; x=sin(2*pi*f*t); figure(1); plot(t,x);
fs1=2*f; n=-1:0.1:1; y1=sin(2*pi*n*f/fs1); figure(2); stem(n,y1);
fs2=1.2*f; n=-1:0.1:1; y2=sin(2*pi*n*f/fs2); figure(3); stem(n,y2);
fs3=3*f; n=-1:0.1:1; y3=sin(2*pi*n*f/fs3); figure(4); stem(n,y3); figure (5);
subplot(2,2,1); plot(t,x); subplot(2,2,2); plot(n,y1); subplot(2,2,3); plot(n,y2); subplot(2,2,4); plot(n,y3);
0 Comments
soumyendu banerjee
on 1 Nov 2019
%% if Fs= the frequency u want,
x = -pi:0.01:pi;
y=sin(Fs.*x);
plot(y)
0 Comments
wilfred nwakpu
on 1 Feb 2020
%%Time specifications:
Fs = 8000; % samples per second
dt = 1/Fs; % seconds per sample
StopTime = 0.25; % seconds
t = (0:dt:StopTime-dt)'; % seconds
%%Sine wave:
Fc = 60; % hertz
x = cos(2*pi*Fc*t);
% Plot the signal versus time:
figure;
plot(t,x);
xlabel('time (in seconds)');
title('Signal versus Time');
zoom xon;
0 Comments
sevde busra bayrak
on 24 Aug 2020
sampling_rate = 250;
time = 0:1/sampling_rate:2;
freq = 2;
%general formula : Amplitude*sin(2*pi*freq*time)
figure(1),clf
signal = sin(2*pi*time*freq);
plot(time,signal)
xlabel('time')
title('Sine Wave')
0 Comments
Ana Maria
on 15 Mar 2023
Implement a function to generate a column vector containing a sine wave, sin(2πf(t)t), with a growing frequency, f(t) from f(0) = f1 to f(T) = f2. The inputs of the function are the duration, T in seconds, the frequencies, f1 and f2, in Hz and the sampling rate, fs, in samples per second x = chirpT one(T, f1, f2, fs)
2 Comments
DGM
on 15 Mar 2023
Edited: DGM
on 16 Mar 2023
You're copying and pasting an assignment text. This is not an answer, so it doesn't belong here as an answer. I'm compelled to keep things where they belong and remove them when they don't.
This is ultimately your task to perform. The information already present on this page is largely sufficient to complete it. I'm sure with enough effort, you can find even more specific examples elsewhere on the forum.
If you want to ask a question, please open a new question using the 'ask' button at the top of the page. If and when you do, ask an actual question, but also be prepared to prove that you've exhausted what due diligence provides.
EDIT:
To prove the point, I'm just going to grab the answer directly above and make one simple change. Other than changing the specific parameters (a matter of choice), the only real change is that instead of being a scalar, freq is a vector generated from two specified values.
% these are parameters
samplerate = 500;
duration = 2;
flim = [0 8];
% both these vectors have the same size
time = 0:1/samplerate:duration; % time is a linear vector
freq = linspace(flim(1),flim(2),numel(time)); % freq is a linear vector
Generating a vector of uniformly-spaced values is very basic MATLAB stuff. The remaining change necessary to make freq work as a vector is also basic (literally one single character), but I have to leave something for you to do.
Avinash Mishra
on 5 May 2023 at 9:04
- Write a MATLAB script to plot a graph with the following specifications.
- Consider two vectors t and y.
- t starts with 0, ends at 15, and contains 400 elements.
y = exp(-0.5*t). *Cos (2*pi. *t).
- Plot y against t. Use a blue (b) dashed (--) line for the plot.
Mark the minimum value m of the vector y by adding a point to the plot. This point should be a red asterisk marker and must be added after the blue line.
1 Comment
DGM
on 5 May 2023 at 17:51
Why did you paste your homework as an answer? This is not an answer to the question, nor is it a question.
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