Simple Linear Algebra problem that's confusing me.
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I'm stuck for the longest time on this problem: Find a row vector l such that lA = l, with A = [.2 .8; .7 .3]. This is somehow related to eigenvalues, is there such thing as a row eigenvector? thanks - Yingquan
1 commentaire
Réponses (1)
Wayne King
le 25 Avr 2012
I don't want to just give you the answer, but think of it this way
1.) Think of the typical eigenvalue problem, I'll use B as the matrix
Bx = \lambda x
2.) if 1 were an eigenvalue of B with some corresponding eigenvector x, then
Bx = x
3.) Now what if you transposed both sides of the above equation and let B'=A (where ' is the transpose)
Now do you see?
2 commentaires
Voir également
Catégories
En savoir plus sur Linear Algebra dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!