How to skip over zero values in an array?

In an array of audio samples, I would like to copy non-zero samples to a different array, and skip over any zero samples. I have tried using a loop to traverse the array, but I am having issues with bounds.

arrayout = [];
% arraycount = 1;

dim = size(dialsound); % number of samples in audio sample I am using
c = 1;

while (c < dim(1,2))
    while(dialsound(1,c) == 0)
        c = c + 1;
    end
    arrayout(1,c) = dialsound(1,c);
    c = c + 1;

end

Answer 1

[Akira Agata]

You can also do that by another way, like:

idx = abs(dialsound) < eps;
arrayout = dialsound(~idx);

[Peter Kapteyn]

Any chance you could explain how this code works? Thanks.

[Akira Agata]

Thank you for your reply. To understand how this code works, I would recommend trying very simple example, like:

>> x = [1 2 0 2 1e-20]
x =
  1.0000    2.0000         0    2.0000    0.0000
>> idx = x < eps
idx =
 0   0   1   0   1
>> y = x(~idx)
y =
   1     2     2

I hope it will be some help for your better understanding !

Answer 2

[Matt J]

Is this what you want

   arrayout=nonzeros(dialsound)