Why do I get the error "Too many input arguments"
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
my_recorder = audiorecorder;
recordblocking(my_recorder,2)
x= getaudiodata(my_recorder);
LPF0=LPF;
x0=filter(LPF0,Num_LPF,1,x);
Code written above is my matlab code.
But when I activated this, "Too many input arguments" message is shown on the command window.
How can I solve this problem?
function Hd = LPF
% MATLAB Code
% Generated by MATLAB(R) 9.2 and the Signal Processing Toolbox 7.4.
% Generated on: 08-Dec-2017 11:47:53
% Equiripple Lowpass filter designed using the FIRPM function.
% All frequency values are in Hz.
Fs = 48000; % Sampling Frequency
Fpass = 200; % Passband Frequency
Fstop = 300; % Stopband Frequency
Dpass = 0.057501127785; % Passband Ripple
Dstop = 0.0001; % Stopband Attenuation
dens = 20; % Density Factor
% Calculate the order from the parameters using FIRPMORD.
[N, Fo, Ao, W] = firpmord([Fpass, Fstop]/(Fs/2), [1 0], [Dpass, Dstop]);
% Calculate the coefficients using the FIRPM function.
b = firpm(N, Fo, Ao, W, {dens});
Hd = dfilt.dffir(b);
% [EOF]
and this is my LPF.
2 commentaires
KSSV
le 8 Déc 2017
Which line shows the error? How did you run the code? It doesn't show any error in my pc.
Réponses (1)
Honglei Chen
le 8 Déc 2017
It should just be
x0=filter(LPF0,x);
the coefficients is already in LPF0.
HTH
1 commentaire
Abhinaba Dey
le 11 Mar 2018
Error using filter2 Too many input arguments.
Error in find_sift (line 48) I_X = filter2(G_X, I, 'same'); % vertical edges
I get the same error. How can I solve it??
Voir également
Catégories
En savoir plus sur 디지털 필터 설계 dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!