Problem in integration function containing gauss hypergeometric function

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Shweta Rajoria
Shweta Rajoria le 14 Déc 2017
I am deriving the coverage probability of heterogeneous network with massive MIMO macro base station. During the process, I am stuck in the in hypergeometric function. The small part of that program is given below.
fun= @(x,y)imag(exp(pi.*1i.*(x).*y.^(-2).*hypergeom(1,[1/2,3/2],-1i.*x./(y.^4))))./x
c= @(y) integral(@(x) fun(x,y), 0.1,1,'ArrayValued',true)
fun1= @(y)((1/2)-((1/pi).*c(y))).*exp(-pi.*y.^2)
c1 = integral(fun1, 0.1,1)
I think iproblem is due to terms(y.^(-2) and and y.^4) in the fun. If any body have any idea please suggest. Any suggestions regarding this will be appreciated.
  7 commentaires
Walter Roberson
Walter Roberson le 9 Jan 2018
Modifié(e) : Walter Roberson le 9 Jan 2018
To within the boundaries of double precision, c1 will be nan. The values involved are way way too big to work with in double precision.
Shweta Rajoria
Shweta Rajoria le 9 Jan 2018
ok sir.. thank you.. but please guide me how this problem can be resolved.

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Réponses (1)

Walter Roberson
Walter Roberson le 8 Jan 2018
fun(8/10, 3/10) is about 2.974*10^1912918 .
fun(8/10, 2/10) is about 4.087*10^-24618734963806
fun(8/10, 0.18) is about 2.345*10^207906652598325658
So, fun is very steep, and has a lot of values that overflow floating point representation. You will not be able to integrate that using any normal representation.
  2 commentaires
Shweta Rajoria
Shweta Rajoria le 9 Jan 2018
Then sir what is the procedure to integrate such problem.
Shweta Rajoria
Shweta Rajoria le 9 Jan 2018
sir, if we are wating for long time, then NaN output comes

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