Effacer les filtres
Effacer les filtres

storing

1 vue (au cours des 30 derniers jours)
nitya ...
nitya ... le 22 Mar 2011
for i=1:N-1
AF=AF+A(i)*2*cos((((2*(i-1))+1)/2)*w)
end
does N-1 values can be stored in the above code

Réponses (2)

the cyclist
the cyclist le 22 Mar 2011
AF = zeros(N-1,1);
for i=1:N-1
AF(i)=AF(i)+A(i)*2*cos((((2*(i-1))+1)/2)*w)
end
  2 commentaires
nitya ...
nitya ... le 22 Mar 2011
for i=1:N-1
A=input('enter A:')
end
if(mod(N,2)==0)
for i=1:N-1
AF=AF+A(i)*2*cos((((2*(i-1))+1)/2)*w)
end
in this code if AF read all the A(i) values
the cyclist
the cyclist le 22 Mar 2011
It is probably mostly a language barrier, but it is not clear what you want to do. Do you want to store all the cumulative sums, as you grow the values of AF? Then you could do what my code does (storing each intermediate value), then use the "cumsum" command to get the intermediate sums.
You need to write a longer, more detailed description of what you need, to get a good answer.

Connectez-vous pour commenter.


Matt Fig
Matt Fig le 22 Mar 2011
I would offer two criticisms of your code. First, you are using the built-in MATLAB variable i as a loop index. This will bite you later when you try to use it as the imaginary unit. Second, you should pre-allocate the variable AF instead of growing it in a loop:
AF = zeros(1,N-1) % Pre-allocation
for ii=1:N-1
AF(ii) = AF(ii) + A(ii)*2*cos((((2*(ii-1))+1)/2)*w);
end

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