How to get the mean of a function when the input of the function is a distribution?
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Jen W
le 15 Jan 2018
Réponse apportée : Torsten
le 15 Jan 2018
I want to get the expectation of y=sin(x) when x follows a distribution described below. But the second line has error. How can I fix this?
x=makedist('Uniform','Lower',0,'Upper',pi/2)
y=sin(x);
mean(y)
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Walter Roberson
le 15 Jan 2018
Modifié(e) : Walter Roberson
le 15 Jan 2018
The easiest approach is the numeric one:
>> mean(sin(random(x,1,10000)))
ans =
0.636616269663442
>> mean(sin(random(x,1,10000)))
ans =
0.636757666186139
>> mean(sin(random(x,1,10000)))
ans =
0.632276664694085
If you need the theoretical answer then rely upon the fact that you have a uniform distribution and calculate the expectation of sin(x) x from 0 to pi/2 symbolically:
syms x
int(sin(x),x,0,pi/2)/(pi/2)
Numerically this comes out as about 0.636619772367581
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Torsten
le 15 Jan 2018
I think you will have to go back to the general definition of the mean of a probability distribution.
Best wishes
Torsten.
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