Circular region in an image

2 vues (au cours des 30 derniers jours)
Sordin
Sordin le 15 Jan 2018
Commenté : Image Analyst le 18 Juil 2018
I am trying to replace a circular region in one image with the corresponding region in another image. Here is my code so far:
% Sample images:
I=imread('office_1.jpg');
I2=imread('office_5.jpg');
[imageSizeY, imageSizeX,z1] = size(I);
centerX = ceil(imageSizeX/2);
centerY = ceil(imageSizeY/2);
radius = 200;
for i=1:max(imageSizeY,imageSizeX)
if (((centerY+i) - centerY).^2 ...
+ ((centerX+i) - centerX).^2 <= radius.^2)
I(centerY:centerY+i, centerX:centerX+i, :) ...
= I2(centerY:centerY+i, centerX:centerX+i, :);
end
end
imshow(I)
Unfortunately, my code does not work correctly, and instead of a circle the result is a square (corresponding to only one quadrant of the desired circle):
What are the mistakes here? Any explanation is greatly appreciated.

Réponse acceptée

Matt J
Matt J le 15 Jan 2018
Modifié(e) : Matt J le 15 Jan 2018
I don't really follow the logic of your code, but in any case there are much simpler and more efficient approaches, e.g.,
[yy,xx,~]=ndgrid( (1:imageSizeY)-centerY, (1:imageSizeX)-centerX ,1:z1);
map=(yy.^2+xx.^2<=radius^2);
I(map)=I2(map);
  3 commentaires
Image Analyst
Image Analyst le 16 Jan 2018
Modifié(e) : Image Analyst le 16 Jan 2018
Does this work for his color image?
Sordin
Sordin le 16 Jan 2018
Hi Image Analyst, Yes this worked for the color images as well.

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Plus de réponses (2)

Image Analyst
Image Analyst le 15 Jan 2018
See my attached copy and paste demos.

Prince Masedi
Prince Masedi le 18 Juil 2018
II. Determine the following statistical parameter using Matlab program (Note you must copy and paste your code on the answer booklet. (1. Error variance, 2. Assume X=Rainfall Y=Runoff fill in the table with respective determined square of (X-Xm) where Xm is the mean of X and determine estimated Y termed as Yest.
  1 commentaire
Image Analyst
Image Analyst le 18 Juil 2018
How does this answer the original question about pasting circular regions into an image?

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