Assigning Multiple Vectors in a Structure Field

I need to assign multiple vectors as the value of a field in a structure. How do I go about doing this? When I try this

for j = 1:2
  for i = 1:3
       basis(j).a(i) = [1 0 0];
  end
end

I get this error: "Subscripted assignment dimension mismatch."

The following works, but I can't use cell arrays.

for j = 1:2
  for i = 1:3
       basis(j).a{i} = [1 0 0];
  end
end

Answer 1

[Walter Roberson]

The fact that a structure is involved is not relevant. You are trying to do the equivalent of

for i = 1:3
 a(i) = [1 0 0];
end

which attempts to store a numeric vector of length 3 into a location that expects only one numeric value.

If you need to store multiple values in a location, then you need to use cell arrays, or you need to use some kind of object-oriented object that can store a vector as a property... which is pretty much the same thing as trying to use a cell array.

Answer 2

[Matt J]

Maybe as follows,

 for j = 1:2
   for i = 1:3
       basis(j).a(i,1:3) = [1 0 0];
    end
 end

Answer 3

[Jos (10584)]

I think you're looking for this:

for j=1:2
   b(j).a = [1 0 0] ; % assign vector to field
end

which can be easier accomplished using deal:

[b2(1:2).a] = deal([1 0 0])