Matlab Curve Fitting via Optimization
Afficher commentaires plus anciens
I have tried to follow this tutorial to fit a curve to my dataset . The equation for the curve should be f(t)=log10((wpmcoeff./(t.^2))+((1.038+3.*log(2.*pi.*1e6.*t)).*fpmcoeff./(t.^2))+(wfmcoeff./t))+(ffmcoeff)+(rwfmcoeff.*t).
I have created the following code:
clock='atomicclockgpsworld.txt';
data=importdata(clock);
carrier=10e6;
sig=data(:,2);
t=data(:,1);
sigsq=log10(sig.^2);
fun = @(coeff)sseval(coeff,t,sigsq);
x0 = rand(5,1);
bestx = fminsearch(fun,x0);
wpmcoeff = bestx(1);
fpmcoeff = bestx(2);
wfmcoeff = bestx(3);
ffmcoeff = bestx(4);
rwfmcoeff = bestx(5);
yfit=log10((wpmcoeff./(t.^2))+((1.038+3.*log(2.*pi.*1e6.*t)).*fpmcoeff./(t.^2))+(wfmcoeff./t))+(ffmcoeff)+(rwfmcoeff.*t);
semilogx(t,sigsq,'x');
hold on
semilogx(t,yfit);
saveas(gcf,'fit','png');
and the corresponding function
function sse = sseval(coeff,t,sigsq)
wpmcoeff = coeff(1);
fpmcoeff = coeff(2);
wfmcoeff = coeff(3);
ffmcoeff = coeff(4);
rwfmcoeff = coeff(5);
sse = sum(sigsq - (log10((wpmcoeff./(t.^2))+((1.038+3.*log(2.*pi.*1e6.*t)).*fpmcoeff./(t.^2))+(wfmcoeff./t)+(ffmcoeff)+(rwfmcoeff.*t))));
end
But the fit produced is horrible (my y data should vary between approximately -20 to -22 but the fit produces a curve that reaches 1e59!). Can anyone suggest where I may be going wrong?

3 commentaires
Torsten
le 16 Fév 2018
You forgot to square the differences between measured data and fit function data.
Furthermore, it might happen that parameters are produced that give complex numbers for your log-expressions in the fit function.
Best wishes
Torsten.
Bethany Baxter
le 16 Fév 2018
Birsen Ayaz-Maierhafer
le 29 Juil 2022
Hi Bethany, I have exactly the the same issue here. Were you ever able to resolve this issue? If so, how? Thank you
Réponses (0)
Catégories
En savoir plus sur Get Started with Curve Fitting Toolbox dans Centre d'aide et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
