hist within a parfor creates transparency violation error?

This code creates a transparency violation error. Is this by design??

s = cell(2,1);

s{1} = randn(100);
s{2} = randn(100);

parfor i=1:2
    figure(i);
    y = s{i};
    hist(y);
end

Answer 1

[Edric Ellis]

hist internally uses inputname to support additional functionality in the resulting plot. Unfortunately, using inputname in a function called from parfor results in the transparency violation error you're seeing. You can work around this by ensuring that the input to hist doesn't have a name (i.e. it's a temporary):

parfor i=1:2
    figure(i);
    y = s{i};
    hist(1 .* y);
    % hist(s{i}) also works
end