Update app.textarea inside a parfor loop
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Error: Valid indices for 'app' are restricted in PARFOR loops.
How would I fix the sliced variable that is 'app' or is it just impossible with parfor and the app designer?
Using Matlab 2017b
Example code below:
clear;
clc;
num_iter=100;
percent=parfor_progress(num_iter);
parfor i=1:num_iter
pause(randi(10));
percent=parfor_progress;
app.TextArea.Value={percent};
end
parfor_progress(0);
Any help/links for further reading would be helpful.
Thanks
Nick
Réponse acceptée
Plus de réponses (1)
Ashadullah Shawon
le 19 Juil 2019
i am just expanding the accepted answer for the quick understanding. I have uploaded the full appdesigner code and here is also the functions preview using parallel.pool.DataQueue and send() and afterEach()
methods (Access = private)
function app= func1(app,data)
%disp(data);
app.textTextArea.Value = strcat('Function 1----',datestr(now));
%pause(1);
app.textTextArea.Value = [app.textTextArea.Value;strcat('Function 1----',datestr(now))];
end
function app= func2(app,data)
%disp('Function 2');
app.textTextArea.Value = [app.textTextArea.Value;strcat('Function 2----',datestr(now))];
%pause(1);
app.textTextArea.Value = [app.textTextArea.Value;strcat('Function 2----',datestr(now))];
end
end
methods (Access = private)
% Value changed function: ClickOnButton
function ClickOnButtonValueChanged(app, event)
q = parallel.pool.DataQueue;
r = parallel.pool.DataQueue;
afterEach(q, @app.func1);
afterEach(r, @app.func2);
parfor i = 1:2
if i == 1
%func1(app);
send(q,i);
else
%func2(app);
send(r,i);
end
end
end
end
3 commentaires
Alexander Babin
le 23 Août 2020
Hi, this didn't work for me: I'm trying to display iteration number each time parfor runs a loop, but it only spits out all messages at once after all of them are compete, not as soon as data.queue receives data it seems
Alexander Babin
le 23 Août 2020
function sendMessage(app,data)
app.ProgressTextArea.Value=[app.ProgressTextArea.Value;data];
end
message = parallel.pool.DataQueue;
afterEach(message, @(msg) sendMessage(app,msg));
parfor iteration=1:N
...
msg = ['Completed iteration # ', num2str(iteration)];
send(message,msg);
end
Walter Roberson
le 23 Août 2020
you might need to add a drawnow call
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