Step function returning NaN values.
Infos
Cette question est clôturée. Rouvrir pour modifier ou répondre.
Afficher commentaires plus anciens
T = A(i,1);
K = A(i,2);
if T==0
T=0.001;
end
s = tf('s');
X= ((-1*s^3)+(-1.533*10e-17*s^2)+(0.0001996*s)+9.227*10e-22)/((s^5)+(-2.602*10e-18*s^4)+(0.00378*s^3)+(6.935*10e-21*s^2)+(1.267*10e-6*s));
Y= 0;
Z= ((-0.01994*s^2)+(-3.174*10e-5))/((s^5)+(-2.602*10e-18*s^4)+(0.00378*s^3)+(6.935*10e-21*s^2)+(1.267*10-6*s));
num=[(0.6*(T^2)*K) 4.8*K*T 9.6*K];
den=[8*T 0];
tfPID=tf(num,den);
itf=X+Y+Z;
jtf=itf*tfPID;
ftf=jtf/(1+jtf);
step(ftf);
dt = 20;
t = 0:dt:800;
e = 1 - step(ftf,t);
H = sum(t'.*abs(e)*dt);
My step function, for varying values of T and K, is giving nan values.I made sure that denominator does not become zero. This is affecting my values in H. How to avoid this? Please help.
Réponses (0)
Cette question est clôturée.
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!