Find position of the values of an array in a second array

5 vues (au cours des 30 derniers jours)
raktim banerjee
raktim banerjee le 25 Jan 2011
There is 2 strings 'dls' & 'look'. I want to find exact lower and exact higher value of every elements of 'dls' in the sorted string 'look'. I wrote this:
dls = [5 2 1 7 4];
look = [-0.6 1 2.6 4.2 5.8 7.4];
s = length(dls);
l = length(look);
dlstr = 0;
dhstr = 0;
for i = 1:s,
for j =1:l,
if dls(i)>=look(j)
continue; %j=j+1;
else
dh = look(j);
dl = look(j-1);
dlstr = [dlstr dl];
dhstr = [dhstr dh];
break;
end
end
end
dhstr(1)=[];
dlstr(1) = [];
dlstr
dhstr
The expected result is:
dlstr =
4.2000 1.0000 -0.6000 5.8000 2.6000
>> dhstr
dhstr =
5.8000 2.6000 1.0000 7.4000 4.2000
but the output is:
dlstr =
4.2000 1.0000 1.0000 5.8000 2.6000
dhstr =
5.8000 2.6000 2.6000 7.4000 4.2000
The problem occurred if any value in both strings match. '1' exists in both string. dlstr(3) should be -0.6000 & dhstr(3) should be 1.000. Please tell me how to overcome this problem?
  2 commentaires
Paulo Silva
Paulo Silva le 25 Jan 2011
"There is 2 strings 'dls' & 'look'"
I disagree, they look like arrays not strings
raktim banerjee
raktim banerjee le 25 Jan 2011
Sorry sir! Yes, those are array.

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Réponse acceptée

Ashish Uthama
Ashish Uthama le 25 Jan 2011
With the above code, this correction should yield you your required output:
dls(i)>look(j)
You might be able to write this functionality more compactly by using the function find. Also: If you find the lower bound first, and the 'look' array is expected to be sorted, then wont the higher bound be the next element?

Plus de réponses (1)

Todd Flanagan
Todd Flanagan le 25 Jan 2011
This:
dls(i)>=look(j)
Should be:
dls(i)>look(j)
You might be able to write this functionality more compactly by using the function find.
Note that because the array is sorted, you can find 1 bound and infer both.
  3 commentaires
raktim banerjee
raktim banerjee le 25 Jan 2011
Thanks a lot. It works.
Ashish Uthama
Ashish Uthama le 25 Jan 2011
yup, its better this way.

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