sprintf with latex problem

108 vues (au cours des 30 derniers jours)
xtremecheez
xtremecheez le 29 Mar 2018
Commenté : Amirali Kamalian le 30 Déc 2019
I just cannot figure out what the problem is with this line, please help. I get this warning sometimes:
Warning: Error updating Text.
Character vector must have valid interpreter syntax:
$ρ_t = 0.26ρ_f, θ_0 = 90°$
Regardless, the subscripts never take. Here is the problematic line:
title(sprintf('$%c_t=%.2f%c_f,%c_0=%2.0f%c$',961,idens,961,952,iang*180/pi,176),'Interpreter','latex');

Réponse acceptée

Walter Roberson
Walter Roberson le 29 Mar 2018
latex cannot have any characters with position greater than 255. That is violated by your 961 (rho) and 952 (theta).
Use \rho and \theta
  3 commentaires
Walter Roberson
Walter Roberson le 29 Mar 2018
The degree character is causing the problem. Use ^{\circ}
xtremecheez
xtremecheez le 29 Mar 2018
That was it, thanks.

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Plus de réponses (1)

Amirali Kamalian
Amirali Kamalian le 30 Déc 2019
Modifié(e) : Amirali Kamalian le 30 Déc 2019
I have a problem quite similar to this:
pltt = '%1.0u: %4u $^{\circ}$C, %4u kg/h';
...
title(sprintf(pltt, j, T, Q),'FontSize', 12,'Interpreter','latex')
When executing this code, I get the following warning:
"String scalar or character vector must have valid interpreter syntax". Furthermore,
"Warning: Escaped character '\c' is not valid."
Any ideas how to fix this?
  2 commentaires
Stephen23
Stephen23 le 30 Déc 2019
You forgot to escape the backslash, i.e. \\circ instead of \circ. This is because you are supplying pltt as the format string to sprintf, so any special characters in it that you want to be treated as literal characters will need to be escaped: you should always check the output of sprintf before using it.
Amirali Kamalian
Amirali Kamalian le 30 Déc 2019
Thanks Stephen!

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