Math problem for code
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I had a matrix S=n*3 (x,y,z) where n is variable change every run and i want to get another variable L1 to Ln where L=sqrt((x2-x1)^2+(y2-y1)^2+(z2-z1)^2) in a matrix contain no of column (n)
0 commentaires
Réponse acceptée
njj1
le 2 Avr 2018
Try using diff(S,1,dim) to get the difference between sequential elements in the matrix S. Each entry in diff(S) is (x_{n} - x_{n-1}, y_{n} - y_{n-1}, z_{n} - z_{n-1}). Then you can square each element of diff(S): (diff(S)).^2. Finally, sum and take the square root: sqrt(sum(diff(S)).^2),dim). In each of these cases, dim is the dimension along which the operation is to take place. So, for the sake of discussion, let's assume S is nx3 (n columns and 3 rows).
diffS = diff(S,1,1);
squaredDiffS = diff.^2;
output = sqrt(sum(squaredDiffS,2));
The output of this code is (n-1)x1, because one column is lost in the diff command.
0 commentaires
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Debugging and Analysis dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!