Effacer les filtres
Effacer les filtres

doubt regarding textscan

4 vues (au cours des 30 derniers jours)
muthu kumar
muthu kumar le 24 Mai 2012
hello friends i want to read a file which contains a long number and i have to store in for further processing, ex 2.6300000000000000e+002 2.2500000000000000e+002() like this . i think it is a exp data ,i tried using textscan(fid,'%f %f')but no result i am waiting for ur help

Réponse acceptée

per isakson
per isakson le 24 Mai 2012
What do you mean by "no result"? What value does fid have? This little test works fine!
str = '2.6300000000000000e+002 2.2500000000000000e+002';
cac = textscan( str,'%f %f');
>> cac{:}
ans =
263
ans =
225
  3 commentaires
Walter Roberson
Walter Roberson le 28 Mai 2012
What result do you get from textscan() ? Do you get an error message?
muthu kumar
muthu kumar le 28 Mai 2012
thank u i got it
the code is
function [c]= file11(arg)
fi=fopen(arg,'r');
c=textscan(fi,'%f %f');
fclose(fi);
main file is
fid = fopen('test.txt');
tline = fgetl(fid);
k=1;
images = cell(1, 2);
while ischar(tline)
disp(tline)
images{k}= file11(tline);
k=k+1;
tline = fgetl(fid);
end
disp([images{:}]);
fclose(fid);
it reads given no of files and it stores the contents in cell array
thank for ur guidence

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Large Files and Big Data dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by