How to visualize two histograms for comparative analysis?

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Alex
Alex le 10 Avr 2018
Basically I have two datasets and I want to perform a comparative analysis by showing how many data fall under a specific range. Any idea as how to do it?
Thanks Alex
  3 commentaires
Anupam Sharma
Anupam Sharma le 12 Déc 2019
This is not working in following code. I am using it exactly as mentioned above but it shows the second histogram only. Can you help ?
% MATLAB R2019a
% Setup
N = [1:5 10 20 40];
LB = 0;
UB = 3;
n = 10000;
% Generate random variates
X = LB + (UB - LB)*rand(max(N),n);
Sn = cumsum(X);
mu = 1.5;
sigma = .75;
S_1 = mu + sigma.*randn(n, 1)
hist1= histogram(Sn(1,:),'Normalization','pdf','EdgeColor', 'blue', 'FaceColor', 'blue')
hold on
hist2 = histogram(S_1(:), 'EdgeColor', 'green', 'FaceColor', 'green', 'FaceAlpha', 0.2);
Image Analyst
Image Analyst le 12 Déc 2019
Use subplot to put them into different axes.

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Réponse acceptée

Image Analyst
Image Analyst le 10 Avr 2018
The histograms will tell you that - how many counts in each range. Use histogram() for visualization, or histcounts() and bar().
  3 commentaires
the cyclist
the cyclist le 11 Avr 2018

Here is an example of using Image Analyst's idea of using both histcounts and bar:

x = randn(2000,1);
y = 0.1 + randn(2000,1);
binRange = -3:0.5:3;
hcx = histcounts(x,[binRange Inf]);
hcy = histcounts(y,[binRange Inf]);
figure
bar(binRange,[hcx;hcy]')
Alex
Alex le 11 Avr 2018
Thanks a lot "the cyclist".

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Plus de réponses (1)

the cyclist
the cyclist le 10 Avr 2018
As shown in the documentation for the histogram histogram, you can plot two overlapping histograms on one figure like this
x = randn(2000,1);
y = 1 + randn(5000,1);
h1 = histogram(x);
hold on
h2 = histogram(y);
If you have the Statistics and Machine Learning Toolbox, you can also use the Kolmogorov-Smirnov test to determine whether the CDFs of the two distributions are statistically different.
  4 commentaires
Image Analyst
Image Analyst le 28 Jan 2022
Try histcounts() and bar()
Milagre MANHIQUE
Milagre MANHIQUE le 28 Jan 2022
Thank you very much, I will proceed as you advise.
I thank you deeply.
Milagre MANHIQUE

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