Copying dynamic array to MxArray object using memcpy in c++
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Hi I am trying to copy a n*m matrix defined by dynamic memory allocation to mxArray, and send it to matlab the matrix is sent right in size but false in values. I appreciate if anyone can help me to find what is wrong. here is the code
double **dataDMA;
int m = 3, n = 3, c = 0;
mxArray *matDDMA;
dataDMA = (double **)calloc(sizeof(double *), m); // number of columns
for (int i = 0; i < m; ++i)
{
dataDMA[i] = (double *)calloc(sizeof(double), n); // number of rows
}
printf("\nMatrix created by Dynamic Memory Allocation:\n");
for (int i = 0; i < n; i++)
{
for (int j = 0; j < m; j++)
{
dataDMA[i][j] = c+1;
printf("%g ", dataDMA[i][j]);
c = c + 1;
}
printf("\n");
}
matDDMA=mxCreateDoubleMatrix(m, n, mxREAL);
if (matDDMA == NULL)
{
printf("Unable to create mxArray matDDMA.\n");
return(EXIT_FAILURE);
}
memcpy((void *)mxGetPr(matDDMA), (void *)dataDMA, m*n *sizeof(double));
engPutVariable(ep, "matDDMA", matDDMA);
engEvalString(ep, "matDDMA");
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James Tursa
le 11 Avr 2018
Modifié(e) : James Tursa
le 11 Avr 2018
Two fundamental problems:
1) You can't guarantee that successive calls to calloc( ) will produce memory segments that are adjacent to each other in memory. So the entire concept of using a single memcpy to copy such memory as one big block is non-conforming. If might happen to work if you are lucky, and then the next time the program will bomb because you weren't lucky. If you want to copy it all as one single block of memory, then you need to allocate it as such. E.g.,
dataDMA = (double **)calloc(sizeof(double *), m); // number of columns
dataDMA[0] = (double *)calloc(sizeof(double), n*m); // entire block of double memory
for (int i = 1; i < m; ++i) // <-- start loop indexing at 1
{
dataDMA[i] = dataDMA[i-1] + n; // next column is n elements over
}
Then, when you are done with this memory you only have two free( ) calls to make:
free(dataDMA[0]);
free(dataDMA);
2) The dataDMA pointer points to the column address array, not to the double data itself. So your memcpy source address is wrong. It should be this:
memcpy(mxGetPr(matDDMA), dataDMA[0], m*n *sizeof(double)); // don't need (void *) here
6 commentaires
James Tursa
le 17 Avr 2018
Does the first value scan in correctly? I would work on just getting this first number to work properly, and then move on to the rest of the file.
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